What are the solutions?
16x^2+9=0

Question

What are the solutions?
16x^2+9=0

anonymous · Answer

I see two perfect squares here... 16 and 9.  what are their components?

anonymous · Answer

3 and 4?

anonymous · Answer

oh wait that says +9...

anonymous · Answer

when in doubt use the quadratic formula i guess...

$$\frac{ \pm \sqrt{-4(16)(9)} }{ 2(16) }$$

anonymous · Answer

i see something wrong here...

anonymous · Answer

$$-\frac{ 3 }{ 4 }i,\frac{ 3 }{ 4 }i$$
$$-\frac{ 4 }{ 3 }i,\frac{ 4 }{ 3 }i$$
$$-\frac{ 3 }{ 4 },\frac{ 3 }{ 4 }$$
$$-\frac{ 9 }{ 16 }i,\frac{ 9 }{ 16 }i$$

anonymous · Answer

ohh its imaginary... thats why

anonymous · Answer

what is the (i) for in these?
i dont understand it and it gets me confused sometimes

anonymous · Answer

ok so you see that quadratic formula that I did up there?  I got the square root of a negative which isn't real.  Those i's in your answer however indicate that the answer is imaginary.

Solving the quadratic equation by taking the negative out and putting an i.

So, you get:

$$\pm \frac{ 3i }{ 4 }$$

anonymous · Answer

oh thanks

anonymous · Answer

can u help me with some more questions?
@piglet9

anonymous · Answer

I can try just mention me and ill try to get to em