Question

what is the value of the derivative of y=(x^5)(lnx) when x=4

Answer 1

what do you get so far?

Answer 2

f'(x)= x^(5)= n( X^(n-1))= 5X^(4)= 5(4)^4)(1/4)

Answer 3

f(x)= ln(x) is (1/x)

Answer 4

waaaattt?

Answer 5

is it not a product rule? how can you separate it into 2 parts like this?

Answer 6

wow! Your right! Sorry lead you the wrong way!

Answer 7

\[f(g(x))'=f'(g(x)g'(x), f(x)=x^5 and g(x)= \ln( x) \]

Answer 8

right ?

Answer 9

nope,

Answer 10

it's not f(g(x)) , it's f(x)* g(x)

Answer 11

\[my calculator says = (5\ln(l/x)-1 ) (x^4)\]

Answer 12

my brain says the same answer with you

Answer 13

confusion! hahaha product rule right ? i"m getting (5x^4)(lnx)+(x^5)/x