Question

Let f(x)=e^(-4x^2)
Find the derivative, f'(x) , and the second derivative, f"(x) .

For my first derivative I have -8xe^(-4x^(2)). Is that right?

Answer 1

it's -8e^(-4x^2)
and the second derivative would be 64e^(-4x^2)

Answer 2

That's right\[\Large f'(x)=-8x e^{-4x^2}\]
You'll have to use the product rule now to find f''

Answer 3

@erigmac that's not correct

Answer 4

thanks! this is where I am not sure about this but is it:
f"(x)=-8e^(-4x^2)+64x^2e^(-4x^2)?

Answer 5

ah, sorry
missed that bit
for the second derivative you are right.

Answer 6

@agent0smith Thank you for correcting me.

Answer 7

Thank you guys, I couldn't figure out why I was getting it wrong but I typed it in wrong.