Let f(x)=e^(-4x^2)
Find the derivative, f'(x) , and the second derivative, f"(x) .

For my first derivative I have -8xe^(-4x^(2)). Is that right?

Question

Let f(x)=e^(-4x^2)
Find the derivative, f'(x) , and the second derivative, f"(x) . 

For my first derivative I have -8xe^(-4x^(2)). Is that right?

anonymous · Answer

it's -8e^(-4x^2)
and the second derivative would be 64e^(-4x^2)

agent0smith · Answer

That's right$$\Large  f'(x)=-8x e^{-4x^2}$$
You'll have to use the product rule now to find f''

agent0smith · Answer

@erigmac that's not correct

anonymous · Answer

thanks! this is where I am not sure about this but is it: 
f"(x)=-8e^(-4x^2)+64x^2e^(-4x^2)?

anonymous · Answer

ah, sorry
missed that bit
for the second derivative you are right.

anonymous · Answer

@agent0smith Thank you for correcting me.

anonymous · Answer

Thank you guys, I couldn't figure out why I was getting it wrong but I typed it in wrong.