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OpenStudy (anonymous):
integral of (sec^2(x))dx ( 0, pi)
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OpenStudy (anonymous):
this is highly interesting
OpenStudy (anonymous):
It makes sense that it would be 0 when you attempt to use FTC 1 because the function is not continuous between (o,pi)
OpenStudy (anonymous):
But I am not sure what method of integration I should be using ? If ITC 1 can not be applied because the integral = is tan(x)
OpenStudy (anonymous):
sorry i never learned this before looks like you're on the right track :D
OpenStudy (anonymous):
Can you please help me?: http://openstudy.com/updates/526082dae4b0c78c62eade37
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