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Pre-Algebra 9 Online
OpenStudy (anonymous):

This is a basic question. since (ab)^m = a^m b^m then (A^2 - B^2) --> (A - B)^2 If that is the case (A-B)^2 --> (A-B)(A-B) --> F -----> A^2 O ---->AB I ----->AB L ----->B^2 therefore A^2 - AB -AB -B^2 = A^2 - 2AB -B^2 Yet my book says: A^3 + B^3 = (A+B)( A^2 -AB+ B^2) I am having problems factoring cubes. Where is my logic wrong? Thank you, and I apologize for the basic question. I am new to this and appreciate your patience.

OpenStudy (anonymous):

I think that instead of I being AB I think it should be BA. Try replacing that

jigglypuff314 (jigglypuff314):

(A^2 - B^2) --> (A - B)^2 is not true (A^2 - B^2) --> (A - B)(A + B) because it is a difference of squares

jigglypuff314 (jigglypuff314):

and as for factoring cubes... (A+B)( A^2 -AB+ B^2) = A(A^2) - A(AB) + A(B^2) + B(A^2) - B(AB) + B(B^2) A^3 - A^2B + AB^2 + A^2B - AB^2 + B^3 A^3 + 0 + 0 + B^3 A^3 + B^3

OpenStudy (anonymous):

I always thought (ab)^m = a^m b^m, raising a product to a power. You have told me this is not true. I will continue to research, since this is a basic principle I have come to know. Thank you.

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