Question

trigonometry question

Answer 1

if y=cot2(x+(pi/4) ) what is theleast positive value for k for which x=k is an asymptote for a function

Answer 2

cotx = cosx/sinx

so for your function, find where sin2(x+pi/4) = 0, as that'll be a vertical asymptote

Answer 3

oh wow, it's that simple?

Answer 4

Yep, then just find the smallest positive value for x

Answer 5

so i would graph it and see?

Answer 6

gotcha, thank you

Answer 7

You could but you can solve that equation by hand

Answer 8

sinx = 0 when x = 0 + n*pi

sin2(x+pi/4) = 0

so 2(x+pi/4) = 0 + n*pi