quadratic equation
2x^4 + 22x^3+56x^2

Question

quadratic equation
2x^4 + 22x^3+56x^2

anonymous · Answer

http://www.wolframalpha.com/input/?i=2x%5E4+%2B+22x%5E3%2B56x%5E2 you are welcome.

akashdeepdeb · Answer

Take 2x^2 common.
And then solve the quad. expression in the parenthesis.

Understood? :)

anonymous · Answer

not really

akashdeepdeb · Answer

@StudentLearner 
That is not considered as helping.
If it was, the very section of Mathematics on OpenStudy could/would have been linked to WolframAlpha.

Explain it, if you know the answer. :)

anonymous · Answer

sorry just trying to help. @AkashdeepDeb

akashdeepdeb · Answer

@power1030
The equation in your question is ACTUALLY biquadratic.
2x^4 + 22x^3+56x^2

Now to convert this into a quadratic equation, we have to take something common in all of the terms.
And that common term is 2x^2

If you take 2x^2 common you'll get,
2x^2(x^2 + 11x + 28)

Now inside the brackets, there is a quadratic equation.
Factorize that. You'll get 2 roots.

And 2x^2 outsde the brackets will give you 2 roots/solutions itself (obvious i should think)


Did ouunderstand this?  :)

akashdeepdeb · Answer

@StudentLearner :D