When 72.0mL of a 0.110M lead(II) nitrate solution is mixed with 112.5mL of a 0.180M potassium iodide solution, a yellow-orange precipitate of lead(II) iodide is formed. What is the molarity of I− in the resulting solution?

Question

jfraser · Answer

you've got a limiting reactant case, where all of the lead ions will be used, but only SOME of the iodide will be used. You have to find the moles of lead ions and moles of iodide ions, then do stoichiometry to find out the moles of iodide left over