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Chemistry 13 Online
OpenStudy (anonymous):

f you have 400.0 mL of water at 25.00 °C and add 120.0 mL of water at 95.00 °C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

OpenStudy (anonymous):

heat capacity of water = 4.184 J/K/g 1mL = 1g 400x4.184x(Tfinal - 25(273))=120x4.184x(Tfinal-95(273)) Tfinal will be in Kelvin

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