Question

How many grams of CO are needed to react with 6.90g of Fe2O3 ?

Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

I just need to know how I would go about approaching this problem! I didn't really understand my instructors explanation! Please help!! ):

Answer 1

There are zoo many problems like this that I would have to do on my assignment so if you I get help on this one, I can figure out the rest! Pleasee help!!!):

Answer 2

Alright have you checked of the equation is balanced?

Answer 3

Thanks for replying!
Yes, it's balanced. What do I do next?

Answer 4

Alright so the way I interpret chemical equations is like this: In this one, you have 1 part Fe2O3 reacting with 3 parts of CO to produce 2 parts of Fe and 3 parts of CO2. So you know how many Fe2O3. Can you find the number of moles?

Answer 5

So are you saying to represent them in mole rations such as 1moleFe2O3 over 3molesCO2 and so on..

Answer 6

Quick question, how do I know which one is reacting with with for future problems? Or are you just going by what the question is asking?

Answer 7

I didn't say what the connection is yet. But I am saying that if you know the amount of any substance in the reaction, you can find the amount of the others. Because basically what it means is that for every 1 mole of Fe2O3 you need 3 moles of CO to react with all the Fe2O3.

And the reactants, the things reacting, are always on the left side or the origin of the arrow. The arrow represents a process that converts something to something.

Answer 8

Oh that's right, I see what you mean about the reactants. Ok so it's saying that 6.90g is the amount of the substance Fe2o3. Is that what you mean? Would I need to convert the Molecular mass of Fe2O3 in grams to moles? Or anything to moles in that matter?

Answer 9

Basically, I just need to know how to set up the equation and if there is something I should convert.? I found similar examples in my text book and class notes but they work with moles so that's why i was wondering if I should convert..

Answer 10

Yes. And yes you need to use the number of moles since that is the only way you can compare amount of different materials since 1g of one substance is not the same as 1g of another. Although you do not convert molecular mass to anything. You do however, convert mass to number of moles WITH THE HELP of molecular mass.

Answer 11

I've figured out the molecular mass for each compound in the equation, I just don't know how to set up the equation.. ):

Answer 12

And yes. Basically for these kind of questions, you first need to write the chemical equation, balance it, and then find the number of mole for any substance you have.

Also, almost every chemical problems require you to find number of moles. This is because as I said before, the number of moles is the only way chemists compare amounts of different chemicals.

This might help from here on http://3.bp.blogspot.com/_6oiP7KBc0Qk/TOyLk2s2UCI/AAAAAAAAACA/9Ax_THrR00c/s1600/molemap.gif

Answer 13

Alright so let me guide you. Can you find the number of moles of whatever substance with known mass? In this case, Fe302

Answer 14

So do I multiply the molecular mass of Fe2O3 by Avogadros number to find the number of moles? Cause I thought it was g/mole .. So 1 mole of Fe2O3 is 159.7 grams.

Answer 15

Thanks again, for helping me btw. I have like 10 problems exactly like this that I can't do because I can't grasp the concept! ):

Answer 16

Did you click on the link I posted? It should help you figure out what to do to get number of moles given the mass.

Answer 17

Yes I did, I'm trying it out now. So I'm multiplying 6.90g X 1 mole over 159.7g which was the Molecular weight of Fe2O3. Is that correct?

Answer 18

That way it would cancel out grams and give me the answer in moles , which turns out to be 0.043 moles rounded up.

Answer 19

Correct. So now you have the amount of Fe302, which represents 1 part in the equation. You require 3 parts of CO so what would you do?

Answer 20

So after that, I'm setting it up as : 0.043 moles of Fe2O3 times the - 3moles of CO2 over 1 mole of Fe2O3.. So basically I'm multiplying 0.043 by 3. is that correct?

Answer 21

Yes correct. And now that you have the number of moles of CO needed, you can convert it back to mass since the question asks for the amount in grams.

Answer 22

https://encrypted-tbn2.gstatic.com/images?q=tbn:ANd9GcRiYr2d21nAYSyjq9YWR47WhACfPeEaQhWqaBTrUMAh1_vhgVFoi6DdZQ

This might be a slightly better chart.

Answer 23

Ok so I got 17.03 g and I used its molecular mass to figure it out.
The first one helped out, I can't really see the second one.. do you maybe have another direct link that I could see? The second link seems extremely zoomed out and when i zoom in, it's really pixelated and I can't see.!

Answer 24

http://chapmannorquay.wikispaces.com/file/view/The_Mole_Map_HQ.jpg/222076898/The_Mole_Map_HQ.jpg This one?

Answer 25

Yess a lot better!!

Answer 26

Alright, well I figured it out. I can finally do the rest! Thank you sooooooo much for guiding me through it, I really appreciate it!!! Youuuu sir, are amazinggggg! THANKS AGAIN!! (:

Answer 27

No problem. I'm glad I could help someone learn something,