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Need quick help! 4 Fe(s) + 3 O2(g) = 2 Fe2O3(s) 72.0 g Fe and 20.0 g O2 calculate the theoretical yield in grams of iron(III) oxide
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1. Convert to moles moles = grams/Molecular mass 2. Determine the limiting reagent (which reagent will be used up first, or simply which reagent will provide the least amount of product (it will give you the smallest amount of moles of product)) 3. Using the limiting reagent determine the amount of product obtained by dividing the moles of the limiting reagent by the integer in front of the reagent you determined to be the limiting reagent, then multiplying the moles by the integer in front of the product. 4. Convert moles to grams using the equation above, that is your theoretical yield
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