How do I approach this problem ? I have attached a picture
tan(76degrees)-tan(76degrees)/1+tan(76degrees)tan(16degrees) and it asks to find A and B

Question

anonymous · Answer

attachment

anonymous · Answer

If this problem would use 45,30,60 degree angles I think I could solve it but my problem is I don't know how to get it to a point where I can use radian measures to solve !

anonymous · Answer

That is just the formula for tan 60 = sqrt(3)

anonymous · Answer

Aren't you allowed to just use the angle sum identity for tangent/?

anonymous · Answer

Yes, thats the formula for tan(76-16) = tan 60 = sqrt (3)

anonymous · Answer

So I substitute sqrt(3) into my give equation and end up with sqrt(3)/1+sqrt(3) ?

anonymous · Answer

$$ \tan (a \pm b) = \frac {\tan a \pm \tan b}{1 \mp \tan a \tan b} $$