Question

how to solve this problem???


If a ball is dropped from the top of a 256-ft building, then the formula
h(t)= 256-16t^2expresses its height h(t) in feet as a function of the time t in seconds.

a. Find h(2), the height of the ball 2 seconds after it is dropped.
b. Find h(4)


-topic about function

Answer 1

help please .. :)

Answer 2

h(t)=256-16y^2
a.
h(2)=256-16(2^2)
h*2=256-16*4
h*2=256-64
h*2=192
divide both sides by 2
h=96
b.
h(4)=256-16(4^2)
h*4=256-16*16
h*4=256-256
h*4=0
divide both sides by 4
h=0

Answer 3

$$
h(t)=256-16y^2\\
a.\\
h(2)=256-16(2^2)\\
h(2)=256-16*4\\
h(2)=256-64\\
h(2)=192\\
\cancel{\text{divide both sides by 2 h=96}} \\
\\
b.\\
h(4)=256-16(4^2)\\
h(4)=256-16*16\\
h(4)=256-256\\
h(4)=0 \\
\cancel{\text{divide both sides by 4 h=0}}
$$