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x=20 cos^3(θ) and y=20 sin^3(θ), find the total length of the curve swept out by the point (x,y) as θ ranges from 0 to 2π.
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isnt it just ds from 0 to 2pi? ds = sqrt((x')^2+(y')^2)
http://tutorial.math.lamar.edu/Classes/CalcII/ParaArcLength.aspx http://tutorial.math.lamar.edu/Classes/CalcII/ParaArcLength_files/eq0008M.gif ^that's what i'd think you need... just dtheta instead of dt.
\[\int_{a}^{b}ds\] \[\int_{0}^{2\pi}\sqrt{(x')^2+(y')^2}dt\]
Paul does a nice job of explaining things :)
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