For what values of a and b will be differentiable for all values of x? Discuss the geometry of the resulting graph of f.
where wer u stuck ?
basically stuck with how to approach this question haha
okie :) First notice its a piecewise function
For a function to be differentiable, 1) It has to be continuous 2) slope must exist at all points
wid that knowledge, setup two equations and sovle \(a\) and \(b\)
i see, so wee need to check for continuity first then. \[\lim_{x \rightarrow 2^-}f(x)=\lim_{x \rightarrow 2^+}f(x)=4a-2b+3\]
f'(x) = 2ax - b = 4a-b = 0?
you need to set left/right limits equal for #1 you need to set the left/right slopes equal for #2
\(\lim_{x \rightarrow 2^-}f(x)= 2a \\ \\ \lim_{x \rightarrow 2^+}f(x)=4a-2b+3\)
set them equal
that takes care of continuity part
ah, i see, so 2a=4a-2b+3 -> 2a-2b+3=0 then f'(x)= a = f'(x)= 4a-b -> 3a-b=0 ?
Perfect !
okay thanks! now im able to find the values!(:
good, next visualizing the graph shoudl be easy
see if u can draw a rough sketch how it looks like...
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