Question

Hey guys!! Plz help me!!! t/f:
When solving inequalities, the addition and subtraction of integers to not affect the inequality sign. A friend of mine says true, but I'm pretty posotive that it's false. Help?

Answer 1

Addition and subtraction doesn't change the sign at all,
However, multiplication or division of a negative will flip the sign,

\(<\rightarrow>, >\rightarrow<~\&~\le\rightarrow\ge,\ge\rightarrow\le\)

Make sense?

Answer 2

but if you do 4-6, you get -2, changing the integer sighn, or -5+6=1, also changing the integer sign.

Answer 3

Lets say for instance you have,

\(6x-4>8\)

What would \(x\) be?

Answer 4

x>2

Answer 5

Correct, now lets change it slightly.

\(-6x-4>8\)

Answer 6

it would still be two because 12 is bigger than 6.

Answer 7

Incorrect, mostly.

\(-6x-4>8\)
\(-6x>12\)

Now, we are dividing by a negative six(-6). That means that we flip the sign.

\(\displaystyle \frac{-6x}{-6}<\frac{12}{-6}\)

\(x<-2\)

Answer 8

oh. so the answer would be true. I get it, thanks austin!!!

Answer 9

Indeed :)
You are very welcome!