Absolute values and solutions Solve |x| = 5 {-5} {5} {-5, 5}(I picked this,but im unsure if its right) Solve 2|x| = 3 {-3/2, 3/2} I really need help with the second one though
In general, \[|a| = \pm a\]
Can you elaborate more
Well, if you're trying to solve for x in this manner, then to solve |x| = 5 you write: \(x = \pm 5\) The \(\pm\) means 'plus or minus' Absolute value is another way of saying 'distance from zero' on a number line. So is someone says |5| is 5, what they are really saying is the distance from 0 to 5 is the same as the distance from 0 to -5, and that distance is 5 units.
Thanks for that do you know anything about the second one?
You isolate the |x| to get \[|x| = \frac{2}{3}\] Then from there, you use the same reasoning from the previous problem to arrive at the correct result.
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