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OpenStudy (anonymous):
2(1.05)^(x)+3=10 solve using log
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OpenStudy (anonymous):
So it's \((2 \times 1.05^x) + 3 = 10\)?
OpenStudy (anonymous):
\[2(1.05)^x+3=10\]
OpenStudy (anonymous):
Ok, same thing. :)
So first you want to get the exponent by itself so you can take the log. I assume you know how to do that.
OpenStudy (anonymous):
I am not sure lol xlog5.1=1??
OpenStudy (anonymous):
I meant do this:
\[2(1.05)^x = 7\]\[(1.05)^x = 3.5\]
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OpenStudy (anonymous):
dude logs are not my friends
OpenStudy (anonymous):
sry i took so long to respond work gets busy then its dead
OpenStudy (anonymous):
It's ok. Logs are nobody's friends. But they can be helpful.
Can you solve it from what I gave you or do you need more?
OpenStudy (anonymous):
yeah one more step lol
OpenStudy (anonymous):
thx
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OpenStudy (anonymous):
\[x = log_{1.05} 3.5\]
OpenStudy (anonymous):
okay but how do you solve that with a ti 83 plus
OpenStudy (anonymous):
Use the change of base formula.
\[\log_b n = \frac{\log_a n}{\log_a b}\](For any a \(\ne\) 1 and b \(\ne\) 1)
OpenStudy (anonymous):
wow thank you just remembered my teacher showing us that formula will not forget that again
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