Question

Solve the system by substitution.
2x+y=-11
3x-4y=11

Answer 1

solve the first equation for y

2x+y=-11

y = -11 - 2x

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then plug this into the second equation


3x-4y=11

3x-4(-11 - 2x)=11

3x + 44 + 8x = 11

11x + 44 = 11

I'll let you finish

Answer 2

would it be (3,5)?

Answer 3

what do you get when you solve 11x + 44 = 11 for x

Answer 4

-3

Answer 5

good

Answer 6

x = -3

use this to find y

Answer 7

how do i find y?

Answer 8

remember we solved for y back in the first equation

Answer 9

so use y = -11 - 2x and plug in x = -3

Answer 10

I'm so confused

Answer 11

y = -11 - 2x

y = -11 - 2(-3) ... replace x with -3 (since x = -3)

y = ???

Answer 12

-5?

Answer 13

yep

Answer 14

so, would it be (-3,-5) or (-5,-3)?

Answer 15

hint: all ordered pair points are of the form (x,y)

Answer 16

You got -3 for x. so in the x position you put -3... you have y = -11 - 2(-3).... this becomes y = -11+ 6, or y= -5.... you have x = -3 and y = -5, ordered pairs are written in (x,y) form... so you have (-3, -5) as your ordered pair