Solve. –6 ≥ 10 – 8x (Points : 1) x ≥ 2 x ≥ –2 x ≤ 2 x ≤ –2
@jim_thompson5910 oh and also thank you for not giving me the answer and making me figure it out because otherwise i would still be stuck do you think you could help me on this one also
im giving another medal
10 – 8x is the same as -8x + 10
so –6 ≥ 10 – 8x is the same as –6 ≥ -8x + 10
it would be -2 and u flip the sign right @jim_thompson5910
what you first do is subtract 10 from both sides –6 ≥ -8x + 10 –6 - 10 ≥ -8x + 10 - 10 -16 ≥ -8x what's next?
do you divide 8 on both sides @jim_thompson5910
-8, yes
the sign will flip
so it would be positive 2
and you flip the sign
so we will have \[\large 2 \le x\] and that turns into \[\large x \ge 2\]
–5t ≥ 65 t ≤ –13 so is this the correct answer for this one
yeah
ok just checking
so the sign never flipped because for the 2 the sign is the same as it was before so does it or does it not flip
well it flips twice once when you divide both sides by a negative number then it does a second time when you flip the whole expression
when I moved that x over I mean
ohhhh okay so it did
5 + d > 5 – d (Points : 1) d > 10 d > 0 d < –5 d > –10
im confused on this one very @jim_thompson5910
what do i do with the 5 where do i move it or change
ok this will be the last one and then I have to go
you subtract 5 from both sides
and that will turn 5 + d > 5 - d into d > -d
ok thnk u for helping
then you add 'd' to both sides to go from d > -d to 2d > 0 and finally you divide both sides by 2 to get d > 0
so would it be -5 or -10
ohhhh so u dont have either number its just a 0
yes exactly
when you subtract 5 from both sides, they go away
may i ask you one more that i had for last because i really dont get this one at all
ok one more
The sum of two consecutive integers is at least 46. What is the least possible pair of integers? (Points : 1) 21 and 23 23 and 24 22 and 23 24 and 25
hint: "The sum of two consecutive integers is at least 46." translates to \[\large x + (x+1) \ge 46\] solve for x
how do u know how to solve all of these lol do you think you could be my algebra tutor
I could help from time to time, yes, or you can ask for help on this website and there are a lot of helpers here too. I know from lots of practice. Basically if x is any number, then x+1 is the next consecutive number so that's how I got x + (x+1) and this must be "at least 46" which means \[\large x + (x+1) \ge 46\]
like do u have gmail kik or anything tht we can stay in contact on
you can message me through here and that works fine I think
and does tht mean the numbers tht add up to it or are the closest
what do you mean?
the question The sum of two consecutive integers is at least 46. What is the least possible pair of integers? (Points : 1) 21 and 23 23 and 24 22 and 23 24 and 25
are u suppose to get the closest numbers or what can add up t this
yeah you have to solve \[\large x + (x+1) \ge 46\] for x. then use this to find x+1
so how do i do tht
i mean how do i find x
I'll get you started \[\large x + (x+1) \ge 46\] \[\large x + x+1 \ge 46\] \[\large 2x+1 \ge 46\] and I'll let you finish up since I have to get going. Good luck
lol ok
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