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\[\sqrt{x^2 +8x}=4\sqrt{3}\]
sorry i cant copy paste that
square both sides, get x^2 + 8x = 48 which is x^2 + 8x - 48 factor that u get (x+12)(x-4)
since (x+12)(x-4) = 0, x = -12 or 4
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ohh ok and i get -12 and 4 right
\(\bf \sqrt{x^2+8x}=4\sqrt{3}\quad \textit{square both sides again}\\ \quad \\ (\sqrt{x^2+8x})^2=(4\sqrt{3})^2\implies \sqrt{(x^2+8x)^2}=4^2\sqrt{3^2}\\ \quad \\\implies x^2+8x=4^2\cdot 3\\ \quad \\ x^2+8x=48\implies x^2+8x-48=0\)
yes
ahh ok thanks
my pleasure :P
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