The predicted equation for total sales over time is given by the equation: Total = 120*ln(t^2 + 0.63) + 50.7 where t is given in months and "Total" is given in thousands of units. Each copy of the movie sells for $14 and costs $7.7 to produce. The sunk cost of producing the film that has not been recovered from theater sales is $5100000 a.) Develop a general, linear profit equation, assuming the cost is linear and using x to represent a single unit of sales. Profit = b.) Find an equation that represents total profit over time by using a composition of functions to change from x units to time
Profit is revenue minus cost. Let \(x\) be the quantity sold. Revenue in terms of quantity is given by: \[ r(x) = 14x \]The cost in terms of quantity sold is given by:\[ c(x) = 7.7x+5100000 \]This means profit would be\[ p(x) = r(x) - c(x) = 14x-(7.7x+5100000)=6.3x-5100000 \]
Now, to find this in terms of time, remember that: \[ x(t) = 120\ln(t^2 + 0.63) + 50.7 \]
Thank you Wio, however for question a, we are looking for "x" to be a single unit of sales
Yes, which is why \(p(x)\) would be profit in terms of sales. Since \(x\) is number of sales.
Oh, ok...
Where as profit in terms of time is just \[\begin{split} (p\circ x)(t) &= p(120\ln(t^2 + 0.63) + 50.7)\\ &=6.3(120\ln(t^2 + 0.63) + 50.7)−5100000\\ &=756\ln(t^2+0.63)-5099680.59 \end{split}\]
Thank you Wio. That is really helpful. So, for break even quantity would I just set 0=6.3x−5100000 and solve for x correct?
Yes.
ok great. I got 809523.809524 for break even qty. How long will it take in months to reach this quantity. How would I set up the equation?
Still there Wio?
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