Question

How Find the domain of the function???
please help........
a. f(x)= 2x, -1 ≤x≤5

b. f(x)= 7/(2x+2)

c. g(x)= (x+10)/(x^2-4)

d. h(x)= √(10&x^2-6x)

e. H(x)= (x^2- 25)/(x+5)

Answer 1

The domain is all values that x can take on.

Answer 2

f(x)= 2x, -1 ≤x≤5 (this gives your limit for x) so it's all values between -1 and +5

Answer 3

yeah.

Answer 4

f(x)= 7/(2x+2)
there is one value that you can't plug in that is -1
f(x) = 7/(2(-1) + 2)
f(x) = 7/0
and you can't have that.
So the domain is all real numbers except -1.

Answer 5

Basically the numbers that make the equation undefined, is what you cannot have. Like for number 3
g(x)= (x+10)/(x^2-4)
if x = 2
g(x) = undefined

Answer 6

if x = 2,-2 *

Answer 7

What values of x make the other one's undefined? @phopXD

Answer 8

As in number 4 and 5.

Answer 9

the values of x is undefined if the other one is a real number For example, 0/0 @shamil98

Answer 10

@mebs help here pls..

Answer 11

For \[h(x) = \sqrt{10x^{2}-6x}\] make it an inequality and solve \[10x^{2} -6x \ge 0 \]

Answer 12

for the last one \[x \in R/ x \neq -5\]

Answer 13

to solve the inequality just factor and go to the number line \[2x(5x -3) \ge 0 \]

Answer 14

uhhh..

Answer 15

just solve \[2x \ge 0 , (5x-3) \ge 0 \]