Question

evaluate the limit.

Answer 1

\[\lim_{x \rightarrow \infty} e^{x -x^{2}}\]

Answer 2

evaluate the exponent when x tends to infinity...since that tends to -infinity....so the limit will tend to e^(-infinity) which is zero

Answer 3

e^x*(1-x)
e^infinity *(-infinity)=e^(-infinity)=1/e^infinity=0

Answer 4

as infinty * infinity= infinity

Answer 5

@mebs

Answer 6

Here is what I tried. let u = -x

so as x approaches -infinity
u approaches infinity ...than I wrote It in terms of u

Answer 7

\[\huge \lim{_{u \rightarrow \infty}} e^{-u-u^{2}}\]

Answer 8

yeah infinity is very very large
its square will also infinity

Answer 9

u did correctly

Answer 10

so its just 0 then