A point is moving along the circle x^2 + (y − 1)^2 = 2 in such a way that its x-coordinate is decreasing at a rate of 1 unit per second. What is happening to the y-coordinate at the instant when the point has reached
(−1, 2)

Question

A point is moving along the circle x^2 + (y − 1)^2 = 2 in such a way that its x-coordinate is decreasing at a rate of 1 unit per second. What is happening to the y-coordinate at the instant when the point has reached 
(−1, 2)

isaiah.feynman · Answer

Implicit differentiation!!!

anonymous · Answer

diff both sides by dt and put dx/dt =-1 and x=-1 y=2 then you can get the value of dy/dt

anonymous · Answer

i tried putting it in y=mx+b form and then i was going to get the derivative but it come out weird.

anonymous · Answer

ooo okay

anonymous · Answer

wait im confused

anonymous · Answer

how do i set it up

isaiah.feynman · Answer

x^2 + (y − 1)^2 = 2 @Dmagic  Differentiate that function implicitly!

isaiah.feynman · Answer

I calculated and saw that the y coordinate is increasing at a rate of 1 unit per second.