Ask your own question, for FREE!
Chemistry 24 Online
OpenStudy (toxicsugar22):

dentify the spectator ions in the following complete ionic equation. Ba2+(aq)+2I−(aq)+2Na +(aq)+SO2−4(aq)→BaSO4(s)+2I−(aq)+2Na+(aq)

OpenStudy (anonymous):

spectator ions are the ones that do not participate in the chemical reaction and therefore remain unchanged. notice that Ba2+ and SO2-4 somehow combined to make BaSO4 while the I- and Na+ ions remain unaffected before and after the arrow. therefore they are said to be spectating

OpenStudy (toxicsugar22):

ok

OpenStudy (toxicsugar22):

so answer is ba2+, SO2-4

OpenStudy (toxicsugar22):

sorry I- and Na+

OpenStudy (anonymous):

yes I- and Na+

OpenStudy (toxicsugar22):

can you help me with one more

OpenStudy (toxicsugar22):

A beaker of nitric acid is neutralized with calcium hydroxide. Write a balanced molecular equation for this reaction.

OpenStudy (toxicsugar22):

is this it 2HNO3(aq) + Ca(OH)2(aq) --> Ca(NO3)2(aq) + 2H2O(l)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

its balanced and everything ^_^

OpenStudy (toxicsugar22):

Write a net ionic equation for this reaction.

OpenStudy (toxicsugar22):

H^+(aq)+ OH^-(aq) --> H2O(l)

OpenStudy (anonymous):

it's right

OpenStudy (toxicsugar22):

ok

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!