Please help me solve for x in the following equation.

x^3+x^2-2=0

What is the process for solving for x in equations like this and of higher degree?

thanks

Question

Please help me solve for x in the following equation.

x^3+x^2-2=0

What is the process for solving for x in equations like this and of higher degree?

thanks

anonymous · Answer

Do you know how to factor it?

agent0smith · Answer

You could check for rational zeroes. Factors of -2, since the coefficient on x^3 is 1.

agent0smith · Answer

Graphically is another method.

anonymous · Answer

Typing 'factor(x^3+x^2-2)' at wolframalpha.com coult help as well.

anonymous · Answer

it would be x^3*x^2=2

agent0smith · Answer

^that isn't helpful @drewsheesley

anonymous · Answer

(x-1)*(x^2 +2x +2)=(x-1)*((x+1)^2 +1)=0
therefore x=1  or  (x+1)^2=-1
               x=1 or x= i-1 or x= -i -1

anonymous · Answer

put x=1
1+1-2=0
0=0
divide by x-1 ,we get
|dw:1382221774107:dw|

anonymous · Answer

the process is euclidean division by trying out roots so you can factorize and then you will have to learn complex numbers and euler equations, depending on how you want to display the results....