What is the vertex of the graph of y = |–x – 3|+ 1?

Question

jdoe0001 · Answer

what value of "x" makes ->  |–x – 3| < -  equals to 0?

anonymous · Answer

i really dont know.. they gave me 4 options 
(3, –1) 

 (4, 0) 

 (0, 4) 

 (–3, 1)

anonymous · Answer

The minimum value of an absolute value function is 0.  @jdoe0001 was asking what value of x gives you the minimum value of |-x - 3|.  Knowing this will give you the solution you desire.

jdoe0001 · Answer

well, look at the absolute value expression

anonymous · Answer

(0,4)? that would be the answer right cayse x is zero?

jdoe0001 · Answer

well.... I mean. what value of "x" makes $\huge  |–x – 3|  = 0$

anonymous · Answer

i dont know thats why i need help

anonymous · Answer

Maybe if the absolute value signs were gone it would help.  Solve -x - 3 = 0.

jdoe0001 · Answer

yeap... so... what do you think?  $\huge -x -3 = 0$

anonymous · Answer

so x would be 3 and y would be -1

anonymous · Answer

-x - 3 = 0.  Check if x = 3 is correct.

jdoe0001 · Answer

-x-3 =0        # x = 3
$\huge -3-3\ne 0$

anonymous · Answer

so which one is it ?????? 
(3, –1) 

 (4, 0) 

 (0, 4) 

 (–3, 1)