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OpenStudy (anonymous):
verify the following identities. HELP PLEASE ! 2. sec^2xcotx-cotx=tanx 3.sinxcosxtanx=1-cosx 4.tanx+cotx=secxcscx
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OpenStudy (anonymous):
2. \[\sec^{2}x = 1+ \tan^{2}x\] \[cotx = \frac{1}{tanx}\] hence, \[[(1+\tan^{2}x)(\frac{1}{tanx})] - \frac{1}{tanx}\]
OpenStudy (anonymous):
you get \[tanx + \frac{1}{tanx} -\frac{1}{tanx} = tanx\]
OpenStudy (anonymous):
for 3. \[tanx = \frac{sinx}{cosx}\] Sub, factor and solve.. for 4. \[secx= \frac{1}{cosx}, cscx= \frac{1}{sinx}\]
OpenStudy (anonymous):
If you can get that on the left side for 4 your good.
OpenStudy (anonymous):
how did you get that on 4?
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OpenStudy (anonymous):
get what?
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