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The reaction rate of an autocatalytic reaction is given by the formula R(x)=kx(a-x) for 0<=x<=a, where a is the initial concentration of substance A and x is the concentration of X. a) Domain? b) graph the function for k=3 and a=8
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I am confused about part b?
plug in the value of k=3 and a=8 in the equation: R(x) = kx(a-x) = 3x(8-x) This is a quadratic expression and the graph of 3x(8-x) will look like a parabola. You can see that for x = 0 and x = 8, 3x(8-x) becomes zero. Those are the roots of the quadratic equation. So the graph will cross the x axis at x = 0 and x = 8. Also if you expand 3x(8-x) it is 24x - 3x^2. When the coefficient of x^2 is negative the parabola faces down or an inverted parabola.
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