Question

In 1934 the biologist G.F. Gause placed 20 paramecia in 5 cc of saline solution with a constant amount of food, and measured the population of the colony on a daily basis. he found that the population f(t) after t days

f(t) = 1049/(1+(e^5.4094-1.0235t))

determine the maximum size of the colony

Answer 1

I tried getting the derivatives, but it's a fraction, so I can't proceed. I got (-1048/(1+e^5.4094-1.0235t)).

Answer 2

This question was asked a year ago, but since that answer doesn't match what I have, I just want to know what is wrong here

Answer 3

i got ((1+e^5.4094-1.0235t)(-1048))/1049^2 instead

Answer 4

i think u meant 1049 instead of -1049?

Answer 5

yeah so i got that part... and when i try finding the derivative, there're 1049^2 in the denominator... and when i set it to 0, e^5.0494-1.0235t = -1, which is impossible..

Answer 6

f'(T)=1049(e^5.4094-1.0235t)

Answer 7

then set to zero

Answer 8

still there?

Answer 9

hi
i was just trying to figure it out

Answer 10

is that f'(t) that you got is the result from 1/f(t)?

Answer 11

no

Answer 12

I thought you were just doing pre-cal and didn't think it was calculus

Answer 13

i need to show full work for full credits :(

Answer 14

that was the derivative

Answer 15

oh this is cal 1

Answer 16

how can you get that? i mean, according to the quotient rule, there should be sth in the denominator.. even if you flip, it still isnt any easier to solve

Answer 17

"A warm Welcome to OpenStudy. I can guide regarding this useful site; ask your doubts from me, for it you can message me. Please use the chat for off topic questions. And remember to give the helper a medal, by clicking on "Best Answer". We follow a code of conduct, ( http://openstudy.com/code-of-conduct ). Please take a moment to read it."