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Mathematics 21 Online
OpenStudy (lena772):

A student needs to make a rectangular cardboard piece that is 12 inches long. The area of the cardboard piece should be between 60 square inches to 300 square inches. The function f(w) relates the area of the cardboard, in square inches, to the width w in inches. Which of the following shows a reasonable domain for f(w)? 2 ≤ w ≤ 5 5 ≤ w ≤ 25 25 ≤ w ≤ 60 60 ≤ w ≤ 300

OpenStudy (lena772):

Not sure, I think it's the last

OpenStudy (lena772):

Even if I'm right can someone explain

terenzreignz (terenzreignz):

Okay, we have piece of cardboard that's \(\underline{definitely}\) going to be 12 inches long, right? So the only unknown is its width...

OpenStudy (lena772):

Ok

terenzreignz (terenzreignz):

If we let its unknown width be w, what's the area of the rectangle?

OpenStudy (lena772):

Area between 60 and 300

OpenStudy (lena772):

area = lxw

terenzreignz (terenzreignz):

Don't take this the wrong way, but I'm really not interested in your guesses... trust me, it's easier than you might make it out to be ^_^

OpenStudy (lena772):

5x12=60, 25x12=300

terenzreignz (terenzreignz):

Length is 12, width is w area is....?

OpenStudy (lena772):

a=12xw

terenzreignz (terenzreignz):

That's right. 12w is the area. And the area has to be between 60 and 300 \[\Large 60 \le 12w \le300\]

OpenStudy (lena772):

so then you divide them both by 12

terenzreignz (terenzreignz):

Yup. Then you get?

OpenStudy (lena772):

5<=12<=25

OpenStudy (lena772):

So it's B... ?

terenzreignz (terenzreignz):

It's not *12* in the middle after you divide all sides by 12 XD

OpenStudy (lena772):

I mean w not 12 sorry

terenzreignz (terenzreignz):

Better. Yes, it's the second choice. Both of your guesses were wrong, so, avoid guessing ^_^

OpenStudy (lena772):

I've had like 3 hours sleep I apologize

OpenStudy (lena772):

Thanks for the help!

terenzreignz (terenzreignz):

No problem.

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