a 21.0 kg box is released on a 35 degree incline and accelerates down the incline at 0.273 m/s^2. Find the friction force impeding its motion. What is the coefficient of kinetic friction?

Question

a 21.0 kg box is released on a 35 degree incline and accelerates down the incline at 0.273 m/s^2.  Find the friction force impeding its motion.  What is the coefficient of kinetic friction?

anonymous · Answer

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anonymous · Answer

I have gotten this far, I just can't figure out what to do from here

anonymous · Answer

you know the mass and the acceleration. You should put them into the equation and then solve the friction force f.

anonymous · Answer

i calculated mgsin(35) = 118.0420
I thought I tried putting this into the homework program we use called WebAssign but I think it said this was wrong???

anonymous · Answer

I think I got it.  Could you check my work?  Is the friction force 112.3090?

anonymous · Answer

Is friction force 112.3090N? and mu 0.6662?

anonymous · Answer

yes, they are correct.