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Mathematics 18 Online
OpenStudy (anonymous):

In my book, i have: "(xy)^n=xy*xy*xy....*xy=x^n y^n" And it says that the reason this is true is beacuse the group is abelian. What does a group being abeliean have to do with the way (xy)^n is multiplied out?

terenzreignz (terenzreignz):

Let's look at a more specific case. Say \[\Large (xy)^2\]

terenzreignz (terenzreignz):

Literally, this means \[\Large (xy)(xy) = xyxy \]right?

OpenStudy (anonymous):

Okay

terenzreignz (terenzreignz):

This will ONLY be equal to \[\Large x^2y^2 = x\color{red}{xy}y\] If we were allowed to switch the positions of these two: \[\Large x\color{blue}{yx}y\] in the first place. IE, only if \[\Large xy = yx \] to begin with, or the group was abelian.

terenzreignz (terenzreignz):

Got it? :D

OpenStudy (anonymous):

so, (xy)(xy)=xyxy, but that is only eequal to x^2y^2=xxyy, if we can change xyxy

terenzreignz (terenzreignz):

if we can change the middle yx into an xy

OpenStudy (anonymous):

okay, that makes sense, thank you

OpenStudy (anonymous):

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