Question

Implicit differentiation

Answer 1

If you guys take the derivative with respect to x for the function \[2y^{3}-3xy+2=0\]

Answer 2

do you guys get \[\frac{3y}{6y^{2}-3x}\]

Answer 3

chain rule and product rul, if you know, this is a piece of cake :)

Answer 4

When you evaluate it at y = 2 (NOT x=2)

do you get \[\frac{2}{8-x}\]

Answer 5

when y= 2, what does x equal ?

Answer 6

nothing it just says evaluate at y = 2

Answer 7

use this : 2y3−3xy+2=0 to find out

Answer 8

in ur derivative square terms should disappear

Answer 9

in the denominator? why? It was 2y^{3} take the derivative and it becomes 6y^{2}?

Answer 10

2*8-6x+2=0

Answer 11

i think your derivative part is correct

Answer 12

i thought it was 2x^2... i need to go check doc :|

Answer 13

wait I know what x is!! x = 3

Answer 14

yes :)

Answer 15

Its alright ganeshie so do I ..so do I