A block, mass 0.68 kg, is "shot" from a spring gun as shown in the figure in the book: The table has a height 0.83 m and is frictionless. If the spring has spring constant k=27 N/m and is originally compressed 0.21 m, how fast will the block be going when it hits the ground?

Question

anonymous · Answer

well we know that the equation for springs is Fs=kx and we are given the spring constant and the compression

anonymous · Answer

27*.21=5.67N

anonymous · Answer

and we know F=ma and we are given the mass so 5.67=.68a

anonymous · Answer

solve for a and the initial acceleration given is 8.3m/s^2

anonymous · Answer

now we use the one dimensional motion equations

anonymous · Answer

$$v ^{2}=2\Delta xa$$ since v0 is zero we can just eliminate it

anonymous · Answer

we get a final velocity of about 4m/s

anonymous · Answer

What did you plug in for delta x?