Question

calculate dy/dt using the given information.
y square root x+1 =12; dx/dt = 8, x=15,y=3

Answer 1

ok i misunderstood the question
it says \(y\sqrt{x+1}=12\)?

Answer 2

yes

Answer 3

then \(y=\frac{12}{\sqrt{x+1}}\) and

\[\frac{dy}{dx}=-\frac{6}{\sqrt{(x+1)^3}}\]
then
\[\frac{dy}{dt}=\frac{dy}{dx}\times \frac{dx}{dt}\] and you are told \(\frac{dx}{dt}=8\)

Answer 4

how did you get the 6

Answer 5

was it from the y=3

Answer 6

\[\frac{ 12 }{ \sqrt{x+1} } = 12\ \left( x+1 \right) ^{\frac{ 1 }{ 2 }}\]

Answer 7

\[\frac{d \left( 12\left( x+1 \right)^\frac{ 1 }{ 2 } \right)}{dx} = \frac{12}{\frac{1}{2}+1}\times \left( x+1 \right)^\left(\frac{1}{2}+1\right)\]

Answer 8

what happen to x = 15

Answer 9

the answer is coming out to be -3/4 and i am still not seeing how that is