Graph the system of inequalities...
\[y \le-x ^{2} \]
\[y >x ^{2}-4\]
These are the two system of inequalities^^^
@Mertsj @Mr.ClayLordMath
Graph: \[ y = - x^2\] Draw a solid line. Shade the inside of the parabola
Graph: \[y=x^2-4\] Make it dotted. Shade the inside of the parabola
i know but im having trouble graphing....
do i like find the vertex first??
@mathstudent55
Just get some ordered pairs. You know they are parabolas so get 3 ordered pairs and use symmetry. If you know how to find the vertex, that would be helpful.
my graph is turning out weird......how do i graphhh???@mathstudent55
@mathstudent55 @Easyaspi314
Ammarah...what's the question? Or is everything clear now?
the question i posted above.....how do i graph iottt
noo one is helping me....and this site is lagging so myuchh
you there?
yes
i still need a lot of help what is wrong with this site...
I will try helping you with one of the inequalities........ I will take the second one, y > x^2 - 4
Before we graph anything, you must realize that the graph itself will be dotted becuase we do not want when y = x^2 - 4, we want the graph of y > x^2 - 4.
Now, the graph of y = x^2 - 4 (which will be dotted), is simply a parabola.....it has x-intercepts of x = 2 and x = -2, and it is U-shaped.
It will look look like this...........
|dw:1382332605265:dw|
Now...we want where y > x^2 -4...so the only question remains is WHERE to shade...inside or outside the parabola..........
The simplest way to determine that...is to take ANY point, say (0,1)...and see whether (0,1) makes the inequality y > x^2 - 4 true or false... let's substitute x = 0 and y = 1, is 1 > (0)^2 - 4 Is 1 > 0 - 4 Is 1 > -4 Answer is YES! Therefore we shade where (0,1) is..that is INSIDE the parabola.. therefore, the graph of y > x^2 - 4 will look like.........
|dw:1382332824812:dw|
Does this makes sense??????
well?
yes but im confused on the first inequality
well, I helped you with the second one. Your welcome!
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