Can anyone help with how to find the x-intercept of a logarithm equation?

Question

aravindg · Answer

It is 1. |dw:1382323402218:dw|

anonymous · Answer

well, I'm trying to find the x-intercept for -log(3)(x-2)+1 which I know the x intercept is 5, but I don't know how to get to that answer, I've tried everything I know.

anonymous · Answer

Same as for any other function ... set y = 0 then solve for x 

like if it was y = log(2) (x + 2) [the (2) is for the base] 

When y = 0, log(2) (x + 2) = 0 

x + 2 = 2^0 [using the definition of log] 

x + 2 = 1 [because 2^0 = 1] 

x = -1

anonymous · Answer

@lahernan this website might help :) http://www.wyzant.com/resources/lessons/math/precalculus/logarithmic_functions

anonymous · Answer

I thought so, Maybe i'm just not doing the math right here is what I keep getting maybe i'm missing something,
3^0=(x-2)+1
1= (x-2)+1
-1          -1
0=x-2
+2  +2
2=x?
Am I missing something?

anonymous · Answer

nope, you are correct.

anonymous · Answer

well thanks for the help