The intervals on which x^2+3X-10 is negative x<-5,-5
please help
if you factor out the equation and set those factors as a table and put the values of the x-intercepts on the bottom you can derive the positive and negative portions of the graph.
can you show me
sure give me a second to draw it.
(x+5)(x-2)
|dw:1382325601195:dw|
so the graph would be positive from -inf to -5, negative from -5 to 2 and positive from 2 to infiniti
r u confused
VERY
the xintercepts on the bottom you get from setting the factored roots to zero. Which at y=0 you get your x-intercepts. So this is a parabola, because of the leading term X^2, so the negative portion of the parabola is going to be between -5 and 2.
you can also just use the formula to find the vertex of a parabola which is -b/2a.
that will tell you kind of a ball park where the bottom of the parabola is at.
still lost :)
if you see the positive and negative symbols on the bottom of the table I drew, those represent when the graph is negative and when it is positive. In the first column before the negative 5 theres two negatives right. So a negative times a negative equals a positive which is where the positive goes on the bottom. If you take the integer just before -5 and plug it into the factored roots on the left it will give you a positive or negative answer and that's where the positive and negatives come from.
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