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Mathematics 7 Online
OpenStudy (anonymous):

The intervals on which x^2+3X-10 is negative x<-5,-52,x>5

OpenStudy (anonymous):

please help

OpenStudy (anonymous):

if you factor out the equation and set those factors as a table and put the values of the x-intercepts on the bottom you can derive the positive and negative portions of the graph.

OpenStudy (anonymous):

can you show me

OpenStudy (anonymous):

sure give me a second to draw it.

OpenStudy (anonymous):

(x+5)(x-2)

OpenStudy (anonymous):

|dw:1382325601195:dw|

OpenStudy (anonymous):

so the graph would be positive from -inf to -5, negative from -5 to 2 and positive from 2 to infiniti

OpenStudy (anonymous):

r u confused

OpenStudy (anonymous):

VERY

OpenStudy (anonymous):

the xintercepts on the bottom you get from setting the factored roots to zero. Which at y=0 you get your x-intercepts. So this is a parabola, because of the leading term X^2, so the negative portion of the parabola is going to be between -5 and 2.

OpenStudy (anonymous):

you can also just use the formula to find the vertex of a parabola which is -b/2a.

OpenStudy (anonymous):

that will tell you kind of a ball park where the bottom of the parabola is at.

OpenStudy (anonymous):

still lost :)

OpenStudy (anonymous):

if you see the positive and negative symbols on the bottom of the table I drew, those represent when the graph is negative and when it is positive. In the first column before the negative 5 theres two negatives right. So a negative times a negative equals a positive which is where the positive goes on the bottom. If you take the integer just before -5 and plug it into the factored roots on the left it will give you a positive or negative answer and that's where the positive and negatives come from.

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