Question

Evaluate this new limit

Answer 1

which limit?

Answer 2

\[\large\lim_{x \to - \infty} \frac{ \sqrt{2x^{2}-1} }{ 3x-5 }\]

Answer 3

I got one positive limit of \[\frac{ \sqrt{2} }{ 3 }\]

Answer 4

You mean - sqrt(2)/3

Answer 5

the original question was:

FInd the vertical and horizontal asymptotes of the equation and graph it . yea

Answer 6

wait -?

Answer 7

Yes, - sqrt(2)/3

x is approaching - infinity, so sqrt(x^2) = -x

Answer 8

Final answer is: - sqrt(2)/3

Answer 9

wait explain it in a math language. you can't really have an x term with the value because it isn't right unless its in the denominator which makes it 0