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OpenStudy (anonymous):
Divide (2x^2+16x+21) ÷ (x+6)
Your answer should give the quotient and the remainder.
12 years ago
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OpenStudy (anonymous):
Look up division of polynomials :) quick youtube videos are easy!
12 years ago
OpenStudy (anonymous):
use... synthetic division
12 years ago
OpenStudy (anonymous):
i got the asnwer but not sure
12 years ago
OpenStudy (anonymous):
remainder is -3?
12 years ago
OpenStudy (anonymous):
yep!
12 years ago
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OpenStudy (anonymous):
whats the quotient
12 years ago
OpenStudy (anonymous):
The quotient is the solution more or less. Like 10+1=11. 11 is your sum
12 years ago
OpenStudy (anonymous):
2x+4?
12 years ago
OpenStudy (jdoe0001):
\(\large {\begin{array}{llccclllll}
-6&|&2&+16&+21\\
&|&&-12&-24\\
\hline\\
&&2&4&3
\end{array}\implies 2x^2+16x+21 \div (x+6)\\ \quad \\
\color{blue}{2x+4+\frac{3}{x+6}}}\)
12 years ago
OpenStudy (jdoe0001):
for the quotient, you "drop" the original polynomial by "1 degree"
12 years ago
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OpenStudy (anonymous):
so iwas right?
12 years ago
OpenStudy (jdoe0001):
yeap
12 years ago
OpenStudy (jdoe0001):
hmmm actually... one sec
12 years ago
OpenStudy (jdoe0001):
+21 - 24 = -3 so....
12 years ago
OpenStudy (anonymous):
ok
12 years ago
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OpenStudy (anonymous):
yea i got that remainder
12 years ago
OpenStudy (jdoe0001):
\(\large {\begin{array}{llccclllll}
-6&|&2&+16&+21\\
&|&&-12&-24\\
\hline\\
&&2&4&-3
\end{array}\implies 2x^2+16x+21 \div (x+6)\\ \quad \\
\color{blue}{2x+4-\frac{3}{x+6}}}\)
12 years ago
OpenStudy (jdoe0001):
ok
12 years ago
OpenStudy (anonymous):
quotient is 2x+4?
12 years ago
OpenStudy (jdoe0001):
yes
12 years ago
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OpenStudy (anonymous):
thanks
12 years ago
OpenStudy (jdoe0001):
the version I posted there is just the expression itself in full.... but yes, in terms of the division, if you keep the remainder, the quotient is just 2x +4
12 years ago
OpenStudy (anonymous):
TY
12 years ago
OpenStudy (jdoe0001):
yw
12 years ago
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