Solve for x. Round your answer to two decimal places. Show your work for full credit.
|dw:1382384833408:dw|
a^2+b^2=c^2
@majdishokri
SOH CAH TOA \[\sin 32 = \frac{20}{x}\]
which is a,b, and c? @MeowMeow123
you have two way each other true but the best like dumbcow way
C is the one you're trying to find, and i don't think the a and b order matters
@MeowMeow123 , 32 is the angle not the 3rd side
\[32^{2}+20^{2}=x ^{2} \to x=\sqrt{32^{2}+20^{2}}\]
37.73
@majdishokri
@ilyautumn , am i wrong this is a simple pythagorean thm problem ?
you're right .
i'm just confused.
@dumbcow but you can solve like this i think your way ??
what a weird problem it actually turns out the 3rd side is basically 32 as well ....haha :)
\[\tan(32) = \frac{20}{y}\] \[y = \frac{20}{\tan(32)} = 32.007\]
@ilyautumn \[\sin(32) = \frac{20}{x}\] \[x = \frac{20}{\sin(32)} = 37.742\]
thats pretty close to the answer that i got when i did it the other way
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