Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

AWARDING MEDALS! Justify if completing the square is a good method for solving when the Discriminant is negative. Use any of your three functions as an example and respond in complete sentences. F(x) = (x-1) (x-2)

OpenStudy (anonymous):

I am not sure how to do this?

OpenStudy (anonymous):

@HaleyT @jdoe0001 @ehuman

OpenStudy (anonymous):

can one of you help me please?

OpenStudy (anonymous):

i'm not sure how to answer this either.

OpenStudy (anonymous):

okay. That is okay. Thanks for looking at it anyways :-)

OpenStudy (anonymous):

@KeithAfasCalcLover @Littlemsadventuretime

OpenStudy (anonymous):

When the discriminant is negative, there are no real roots! So completing the square will only give you the co-ordinates. It has no real roots

OpenStudy (anonymous):

thanks guys! I will look at that link now @ehuman

OpenStudy (anonymous):

I am gonna work it out and then post what I did to see if it is right

OpenStudy (anonymous):

okay so first, I used the distributive property and I got x^2+x-2. Then I set it to 0 right?

OpenStudy (anonymous):

rule# 2. If the discriminant is negative, there are two conjugate complex solutions. So I would imagine that the quadratic should be used to find the complex solutions I think rule 3 fits your situation: 3. If the discriminant is positive, there are two real solutions. A. If the discriminant is a perfect square, the two real solutions are rational. B. If the discriminant is not a perfect square, the two real solutions are irrational..

OpenStudy (anonymous):

Well not that it fits your question, but a plus for when to use completing the square.

OpenStudy (anonymous):

okay :-) So is the question asking me to solve the equation?

OpenStudy (anonymous):

no, it is asking if completing the square is the right operation if the conjugate is negative, and tell why, read those three rules from the link and you should have justification and an explanation to give.

OpenStudy (anonymous):

okay! Thank you very VERY much for your help!

OpenStudy (anonymous):

I have to log off, good luck I'll check back in later.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!