Charge of the second particle help please? Force exerted on particle with 5.0x10^-9 C by second particle that is 4 cm away is 8.4x10^-5 N.
I thought maybe it would be 3.0x10^-9?
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do you have the equation for electrical force? or it could be called columbs law?
Correct?
yep! thats the one!
in the problem we are given: F, q1, r. but we don't know q2 and k. k is a constant, do you have that? and q2 is what we are solving for. so once we get k, we can solve for the answer.
@J.Velasquez do you have what k equals in your notes?
I'm not sure if its this one, but I have 8.9 written next to k.
like this 8.9 x 10^9 N • m2 / C2
do you have if figured out, or do you should i walk you through the next step?
@j.velasquez
I think I can solve, but can you just help me on what are the values? >.< Obviously the K is the 8.9 value but I don't know where the other ones fit in. Thanks for your help btw!
sorry, back so here are the values we have figured out: F = 8.4x10^-5 k = 8.9 x 10^9 q1 = 5x10^-9 r = 0.04 meters (every time this equation is use, we have to use meters, not cm) q2 = ? [solve for]
hint, you answer should be between 2.7x10^-9 to 3.5x10^-9
Thank you so much! (:
ur welcome
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