Question

Find the value of tan θ for the angle shown.

Answer 1

wheres the angle?

Answer 2

^right there

Answer 3

notice the coordinates for the point, \(\large \begin{array}{llll}
&x&y\\
&cosine&sine\\
(&\sqrt{33}\quad ,\quad &-4)\\ \quad \\
&&tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\implies \cfrac{y}{x}

\end{array}\)

Answer 4

- sqrt(33)/4

Becuase that is a 4th quadrant angle where the tangent of that angle is negative.

And tangent of theta is just y/x by definition.

Answer 5

sorry...-4/sqrt(33)

Answer 6

-4/√33

Answer 7

theres not option for that

Answer 8

tan θ = negative square root of thirty-three divided by four

tan θ = negative four times square root of thirty-three divided by thirty-three

tan θ = negative four-sevenths

tan θ = negative square root of thirty-three divided by seven

Answer 9

because you'd have to simplify it

Answer 10

so simplify it by getting rid of the radical in the denominator

Answer 11

what is it ?

Answer 12

multiply top and bottom by the denominator