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MIT 6.002 Circuits and Electronics, Spring 2007 17 Online
OpenStudy (anonymous):

∫(sinx × cos2nx)dx

OpenStudy (anonymous):

hi, i suppose the answer should be this........... integral sin(x) cos(2 n x) dx = (2 n sin(x) sin(2 n x)+cos(x) cos(2 n x))\/(4 n^2-1)+constant

OpenStudy (anonymous):

\[\int\limits_{}^{}sinxcos2nx=1/2n*\sin2nx*sinx-1/2n \int\limits_{}^{}\sin2nx*cosxdx .Finish the problem using integration by parts..\]

OpenStudy (anonymous):

Finish the problem using integration by parts.

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