Question

Solve each of the following. Please give both the general solution and the specific solutions in the given interval.

Answer 1

@Easyaspi314

Answer 2

looks more like solving trig equations than calculus :)

Answer 3

for q1, isolate the sin(2x)
\[\sin(2x) = -\frac{\sqrt{3}}{2}\]
use your unit circle to find angles corresponding to sine value of -sqrt3/2

Answer 4

It's Trig Review, I'm just starting the calc course.

Answer 5

That's a question I have, does the -sqrt3/2 have to be in the first value or the second?

Answer 6

(cos ,sin)

sine is always 2nd value , like the "y"

Answer 7

ok give me a sec I'm gonna look at the circle :)

Answer 8

4pi/3, 5pi/3, pi/3

Answer 9

Correct?

Answer 10

yes except for pi/3 ... that gives a positive value

Answer 11

Okay

Answer 12

So those are 2 values, what about the interval?

Answer 13

4pi/3 + 1pi

Answer 14

right?

Answer 15

the interval applies to x....but we just found angles for 2x so that interval is doubled (0,4pi)

....almost add 2pi not just pi

Answer 16

adding 2pi gets you full circle back at same spot

Answer 17

Why don't you add 1pi isn't the general formula 4pi/3 + n pi

Answer 18

I'm not arguing I'm just wondering :S

Answer 19

depends sometimes formula is +npi or +2npi
in this case when you just add pi you change the sign to positive which is not a solution

Answer 20

I'm confused :/