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Mathematics 13 Online
OpenStudy (anonymous):

let ABC be a well-defined product of matrices. suppose that A,C are both invertible. Prove that rank(ABC) = rank (b)

OpenStudy (anonymous):

Like does this have to do with A^TA cancels out??

OpenStudy (anonymous):

so A and C are invertible (And hence square) lets say A is a n x n matrix and C is a m x m matrix so we know that rank(A) = n and rank(C) = m and B have to be a matrix of n x m since ABC is a well defined product now can you use this fact : Rank(AB) = Rank(B) (it works in our case since A is rank n and B itself is n x m) ?

OpenStudy (anonymous):

by can you use it i ask if you know it and we dont have to prove it also

OpenStudy (anonymous):

I guess you managed to do it?

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