A 0.50kg wooden block is placed on top of a 1.0 kg wooden block. the coefficient of static friction between the two blocks is 0.35, and the coefficient of kinetic friction between the lower block and the level table is 0.20. What is the maximum horizontal force that can be applied to the lower block without the upper block slipping?

Question

anonymous · Answer

draw a free body diagram to start off

anonymous · Answer

|dw:1382409717394:dw|

anonymous · Answer

yeah thats good enough

anonymous · Answer

now find the force due to friction between the two blocks

anonymous · Answer

is it 0.5*0.35*9.8 = 1.715 ?

anonymous · Answer

now use f=ma to determine the acceleration of the upper block when 1.75N of force is applied to it

anonymous · Answer

remember you only want the acceleration of the upper block, so only use the mass of the upper block

anonymous · Answer

1.75 = 0.5a, a = 3.5

anonymous · Answer

how is the 1.75N part related to the question...? is it just a random number?